MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2

MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2

Question 1.
Give first the step you will use to separate the variable and then solve the equation:
(a) x – 1 = 0
(b) x + 1 = 0
(c) x – 1 = 5
(d) x + 6 = 2
(e) y – 4 = -7
(f) y – 4 = 4
(g) y + 4 = 4
(h) y + 4 = -4
Solution:
On adding 1 to both sides of the given equation, we obtain
x – 1 + 1 = 0 + 1 ⇒ x = 1

(b) x + 1 = 0
On subtracting 1 from both sides of the given equation, we obtain
x + 1 – 1 = 0 – 1 ⇒ x = -1

(c) x – 1 = 5
On adding 1 to both sides of the given equation, we obtain
x – 1 + 1 = 5 + 1 ⇒ x = 6

(d) x + 6 = 2
On subtracting 6 from both sides of the given equation, we obtain
x + 6 – 6 = 2 – 6 ⇒ x = -4

(e) y – 4 = – 7
On adding 4 to both sides of the given equation, we obtain
y – 4 + 4 = -7 + 4 ⇒ y = -3

(f) y – 4 = 4
On adding 4 to both sides of the given equation, we obtain
y – 4 + 4 = 4 + 4 ⇒ y = 8

(g) y + 4 = 4
On subtracting 4 from both sides of the given equation, we obtain
y + 4 – 4 = 4 – 4 ⇒ y = 0

(h) y + 4 = -4
On subtracting 4 from both sides of the given equation, we obtain
y + 4 – 4 = – 4 – 4 ⇒ y = -8

MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2

Question 2.
Give first the step you will use to separate the variable and then solve the equation:
(a) 3l = 42
(b) \(\frac{b}{2}\) = 6
(c) \(\frac{p}{7}\) = 4
(d) 4x = 25
(e) 8y = 36
(f) \(\frac{z}{3}=\frac{5}{4}\)
(g) \(\frac{a}{5}=\frac{7}{15}\)
(h) 20t = -10
Solution:
(a) 3l = 42
On dividing both sides of the given equation by 3, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 1

(b) \(\frac{b}{2}\) = 6
On multiplying both sides of the given equation by 2, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 2

(c) \(\frac{p}{7}\) = 4
On multiplying both sides of the given equation by 7, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 3

(d) 4x = 25
On dividing both sides of the given equation by 4, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 4

(e) 8y = 36
On dividing both sides of the given equation by 8, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 5

(f) \(\frac{z}{3}=\frac{5}{4}\)
On multiplying both sides of the given equation by 3, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 6

(g) \(\frac{a}{5}=\frac{7}{15}\)
On multiplying both sides of the given equation by 5, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 7

(h) 20t = -10
On dividing both sides of the given equation by 20, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 8

MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2

Question 3.
Give the steps you will use to separate the variable and then solve the equation:
(a) 3n – 2 = 46
(b) 5m + 7 = 17
(c) \(\frac{20 p}{3}\) = 40
(d) \(\frac{3 p}{10}\) = 6
Solution:
(a) 3n – 2 = 46
On adding 2 to both sides, we obtain
3n – 2 + 2 = 46 + 2 ⇒ 3n = 48
On dividing both sides of the given equation by 3, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 9

(b) 5m + 7 = 17
On subtracting 7 from both sides, we obtain
5m + 7 – 7 = 17 – 7 ⇒ 5m = 10
On dividing both sides of the given equation by 5, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 10

(c) \(\frac{20 p}{3}\) = 40
On multiplying both sides of the given equation by 3, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 11
On dividing both sides of the given equation by 20, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 12

(d) \(\frac{3 p}{10}\) = 6
On multiplying both sides of the given equation by 10, we obtain 3pxl0
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 13
On dividing both sides of the given equation by 3, we obtain
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 14

Question 4.
Solve the following equations:
(a) 10p = 100
(b) 10p + 10 = 100
(c) \(\frac{p}{4}\) = 5
(d) \(\frac{-p}{3}\) = 5
(e) \(\frac{39}{4}\) = 6
(f) 3s = -9
(g) 3s + 12 = 0
(h) 3s = 0
(i) 2q = 6
(j) 2q – 6 = 0
(k) 2q + 6 = 0
(l) 2q + 6 = 12
Solution:
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 15
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 16
MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2 17

MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.2

MP Board Class 7th Maths Solutions

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